In this part we’ll define continuity when dealing with functions with several variables. We’ll also start looking at derivatives of functions of several variables.
Continuity
Let’s recall what continuity of a function with one variable is defined:
A function of one variable is continuous at a point, a∈D if:
x→alimf(x)=f(a)
In functions with several variables, it’s the same:
(x,y)→(a,b)limf(x,y)=f(a,b)
We say f is continuous on its domain, if f is continuous at each point, (a,b)∈D
Continuity laws
Suppose fandg are functions of two variables. h, is a function of one variable. Which are continuous in their respective domains, then:
f±gf⋅g(gf)h(f(x,y))
All of the above, are continuous on their domains.
Example
f(x,y)=x∣ is continuous at R2
Proof:
(x,y)→(a,b)limf(x,y)=f(a,b)=aUsing the limit law: (x,y)→(a,b)limx=a
Similarly f(x,y)=y is continuous at R2.
f(x,y)=x3y−y2+x∣ is continuous at R2
Proof:
Since polynomials are combinations of f(x,y)=x and f(x,y)=y, using continuity laws (or limit laws), we can easily prove this.
f(x,y)=y−xx3y3−x4y∣ is continuous on its domain
The domain of f is:
{(x,y)∣y−x=0}f(x,y)=ex2−y∣ is continuous at R2
Using the composition law of continuity, we easily prove that this function is a continuous function, on its domain. In this case it’s still R2.
Knowing whether a function is continuous or not is very powerful, knowing that the above function is continuous makes:
(x,y)→(a,b)limex2−y=e12−3=e−2
Trivial.
Determine if this function is continuous:
f(x,y)=⎩⎨⎧x2+3y4xy20(x,y)=(0,0)(x,y)=(0,0)
Solution:
If the function is continuous, using the definition, then:
As we have seen continuity is quite similar when dealing with functions of several variables. The partial derivate of functions of several variables are also quite trivial since we treat the other variables as constants!